t(t+3)-t(t-5)=4(t-5)-7(t-3)

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Solution for t(t+3)-t(t-5)=4(t-5)-7(t-3) equation: 



t(t+3)-t(t-5)=4(t-5)-7(t-3)

We move all terms to the left:

t(t+3)-t(t-5)-(4(t-5)-7(t-3))=0

We multiply parentheses

t^2-t^2+3t+5t-(4(t-5)-7(t-3))=0



We calculate terms in parentheses: -(4(t-5)-7(t-3)), so:

4(t-5)-7(t-3)

We multiply parentheses

4t-7t-20+21

We add all the numbers together, and all the variables

-3t+1

Back to the equation:

-(-3t+1)



We add all the numbers together, and all the variables

8t-(-3t+1)=0

We get rid of parentheses

8t+3t-1=0

We add all the numbers together, and all the variables

11t-1=0

We move all terms containing t to the left, all other terms to the right

11t=1

t=1/11

t=1/11

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