t(t+3)=42

Solution for t(t+3)=42 equation:

t(t+3)=42

We move all terms to the left:

t(t+3)-(42)=0

We multiply parentheses

t^2+3t-42=0

a = 1; b = 3; c = -42;
Δ = b2-4ac
Δ = 32-4·1·(-42)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{177}}{2*1}=\frac{-3-\sqrt{177}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{177}}{2*1}=\frac{-3+\sqrt{177}}{2}
$