t(t+4)-2=t(t+2)+2

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Solution for t(t+4)-2=t(t+2)+2 equation: 



t(t+4)-2=t(t+2)+2

We move all terms to the left:

t(t+4)-2-(t(t+2)+2)=0

We multiply parentheses

t^2+4t-(t(t+2)+2)-2=0



We calculate terms in parentheses: -(t(t+2)+2), so:

t(t+2)+2

We multiply parentheses

t^2+2t+2

Back to the equation:

-(t^2+2t+2)



We get rid of parentheses

t^2-t^2+4t-2t-2-2=0

We add all the numbers together, and all the variables

2t-4=0

We move all terms containing t to the left, all other terms to the right

2t=4

t=4/2

t=2

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