t+22+1t=3(2t-6)

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Solution for t+22+1t=3(2t-6) equation: 



t+22+1t=3(2t-6)

We move all terms to the left:

t+22+1t-(3(2t-6))=0

We add all the numbers together, and all the variables

2t-(3(2t-6))+22=0



We calculate terms in parentheses: -(3(2t-6)), so:

3(2t-6)

We multiply parentheses

6t-18

Back to the equation:

-(6t-18)



We get rid of parentheses

2t-6t+18+22=0

We add all the numbers together, and all the variables

-4t+40=0

We move all terms containing t to the left, all other terms to the right

-4t=-40

t=-40/-4

t=+10

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