t+3+(8/t)=0

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Solution for t+3+(8/t)=0 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

t+8/t+3 = 0

1*t^1+8*t^-1+3*t^0 = 0

(1*t^2+3*t^1+8*t^0)/(t^1) = 0 // * t^2

t^1*(1*t^2+3*t^1+8*t^0) = 0

t^1

t^2+3*t+8 = 0

t^2+3*t+8 = 0

DELTA = 3^2-(1*4*8)

DELTA = -23

DELTA < 0

t in { } 

t belongs to the empty set

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