t-2(3-2t)=21+

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Solution for t-2(3-2t)=21+ equation: 



t-2(3-2t)=21+

We move all terms to the left:

t-2(3-2t)-(21+)=0

We add all the numbers together, and all the variables

t-2(-2t+3)-0=0

We add all the numbers together, and all the variables

t-2(-2t+3)=0

We multiply parentheses

t+4t-6=0

We add all the numbers together, and all the variables

5t-6=0

We move all terms containing t to the left, all other terms to the right

5t=6

t=6/5

t=1+1/5

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