t-2=(3t/10)+5

Solution for t-2=(3t/10)+5 equation:

t-2=(3t/10)+5

We move all terms to the left:

t-2-((3t/10)+5)=0

We add all the numbers together, and all the variables

t-((+3t/10)+5)-2=0

We multiply all the terms by the denominator


t*10)+5)-((+3t-2*10)+5)=0

We add all the numbers together, and all the variables

t*10)+5)-((3t-20)+5)=0

We add all the numbers together, and all the variables

t*10)+5)-((3t=0

Wy multiply elements

10t^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{20}=0$