t1+t2=88

Solution for t1+t2=88 equation:

t1+t2=88

We move all terms to the left:

t1+t2-(88)=0

We add all the numbers together, and all the variables

t^2+t-88=0

a = 1; b = 1; c = -88;
Δ = b2-4ac
Δ = 12-4·1·(-88)
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{353}}{2*1}=\frac{-1-\sqrt{353}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{353}}{2*1}=\frac{-1+\sqrt{353}}{2}
$