t2+26t=27

Solution for t2+26t=27 equation:

t2+26t=27

We move all terms to the left:

t2+26t-(27)=0

We add all the numbers together, and all the variables

t^2+26t-27=0

a = 1; b = 26; c = -27;
Δ = b2-4ac
Δ = 262-4·1·(-27)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-28}{2*1}=\frac{-54}{2}
=-27
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+28}{2*1}=\frac{2}{2}
=1
$