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t2+7t+-35=2t+-11
We move all terms to the left:
t2+7t+-35-(2t+-11)=0
We add all the numbers together, and all the variables
t2+7t-(2t-11)-35+=0
We add all the numbers together, and all the variables
t^2+7t-(2t-11)=0
We get rid of parentheses
t^2+7t-2t+11=0
We add all the numbers together, and all the variables
t^2+5t+11=0
a = 1; b = 5; c = +11;
Δ = b2-4ac
Δ = 52-4·1·11
Δ = -19
Delta is less than zero, so there is no solution for the equation
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