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t2-10t+25=0
We add all the numbers together, and all the variables
t^2-10t+25=0
a = 1; b = -10; c = +25;
Δ = b2-4ac
Δ = -102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{10}{2}=5$
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