t2-21t+110=0

Solution for t2-21t+110=0 equation:

t2-21t+110=0

We add all the numbers together, and all the variables

t^2-21t+110=0

a = 1; b = -21; c = +110;
Δ = b2-4ac
Δ = -212-4·1·110
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-1}{2*1}=\frac{20}{2}
=10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+1}{2*1}=\frac{22}{2}
=11
$