t2-26t=56

Solution for t2-26t=56 equation:

t2-26t=56

We move all terms to the left:

t2-26t-(56)=0

We add all the numbers together, and all the variables

t^2-26t-56=0

a = 1; b = -26; c = -56;
Δ = b2-4ac
Δ = -262-4·1·(-56)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-30}{2*1}=\frac{-4}{2}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+30}{2*1}=\frac{56}{2}
=28
$