t2-3t-2t+10=t2-5t+10

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Solution for t2-3t-2t+10=t2-5t+10 equation: 



t2-3t-2t+10=t2-5t+10

We move all terms to the left:

t2-3t-2t+10-(t2-5t+10)=0

We add all the numbers together, and all the variables

-(+t^2-5t+10)+t2-3t-2t+10=0

We add all the numbers together, and all the variables

t^2-(+t^2-5t+10)-5t+10=0

We get rid of parentheses

t^2-t^2+5t-5t-10+10=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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