t=2-22t-3(1-t)

Solution for t=2-22t-3(1-t) equation:

t=2-22t-3(1-t)

We move all terms to the left:

t-(2-22t-3(1-t))=0

We add all the numbers together, and all the variables

t-(2-22t-3(-1t+1))=0


We calculate terms in parentheses: -(2-22t-3(-1t+1)), so:

2-22t-3(-1t+1)

determiningTheFunctionDomain
-22t-3(-1t+1)+2

We multiply parentheses

-22t+3t-3+2

We add all the numbers together, and all the variables

-19t-1

Back to the equation:

-(-19t-1)


We get rid of parentheses

t+19t+1=0

We add all the numbers together, and all the variables

20t+1=0

We move all terms containing t to the left, all other terms to the right

20t=-1

t=-1/20

t=-1/20