t=2r+3;5r-4t=6

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Solution for t=2r+3;5r-4t=6 system of equations: 


  • /| t-(2*r)-3 = 0| 5*r-(4*t)-6 = 0
  • We try to solve the equation: t-(2*r)-3 = 0
  • t-2*r-3 = 0 // + -2*r-3
  • t = -(-2*r-3)
  • t = 3-(-2*r)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 5*r-(4*(3-(-2*r)))-6 = 0| t = 3-(-2*r)
  • 5*r-1*4*(2*r+3)-6 = 0
  • -3*r-12-6 = 0
  • -3*r-18 = 0
  • -3*r-18 = 0 // + 18
  • -3*r = 18 // : -3
  • r = 18/(-3)
  • r = -6
  • We insert the solution into one of the initial equations of our system of equations
  • For t = 3-(-2*r): 
  • t = 3-(-6*(-2))
  • t = 3-(2*6)
  • t = 3-12
  • t = -9
  • We get a system of equations:
  • /| t = -9| r = -6

 

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