tan(62)=x/15

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Solution for tan(62)=x/15 equation:


D( x )

cos(62) = 0

cos(62) = 0

cos(62) = 0

t_1 = cos(62)

cos(62) = 0

t_1 = 0

x należy do R

x in (-oo:+oo)

x belongs to the empty set

tan(62) = x/15

x belongs to the empty set

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