u(u-5)+8u=u(I+2)-4

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Solution for u(u-5)+8u=u(I+2)-4 equation: 



u(u-5)+8u=u(+2)-4

We move all terms to the left:

u(u-5)+8u-(u(+2)-4)=0

We add all the numbers together, and all the variables

u(u-5)+8u-(u2-4)=0

We add all the numbers together, and all the variables

8u+u(u-5)-(u2-4)=0

We multiply parentheses

u^2+8u-5u-(u2-4)=0

We get rid of parentheses

u^2+8u-5u-u2+4=0

We add all the numbers together, and all the variables

3u+4=0

We move all terms containing u to the left, all other terms to the right

3u=-4

u=-4/3

u=-1+1/3

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