u+1/u+3+1=u+2/u-4

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Solution for u+1/u+3+1=u+2/u-4 equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

u+1/u+1+3 = u+2/u-4 // - u+2/u-4

u-u+1/u-(2/u)+1+3+4 = 0

u-u+1/u-2*u^-1+1+3+4 = 0

-1*u^-1 = -8 // : -1

u^-1 = 8

-1 < 0

1/(u^1) = 8 // * u^1

1 = 8*u^1 // : 8

1/8 = u^1

u = 1/8

u = 1/8

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