u+3(u-4)=4(u-5)

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Solution for u+3(u-4)=4(u-5) equation: 


Simplifying
u + 3(u + -4) = 4(u + -5)

Reorder the terms:
u + 3(-4 + u) = 4(u + -5)
u + (-4 * 3 + u * 3) = 4(u + -5)
u + (-12 + 3u) = 4(u + -5)

Reorder the terms:
-12 + u + 3u = 4(u + -5)

Combine like terms: u + 3u = 4u
-12 + 4u = 4(u + -5)

Reorder the terms:
-12 + 4u = 4(-5 + u)
-12 + 4u = (-5 * 4 + u * 4)
-12 + 4u = (-20 + 4u)

Add '-4u' to each side of the equation.
-12 + 4u + -4u = -20 + 4u + -4u

Combine like terms: 4u + -4u = 0
-12 + 0 = -20 + 4u + -4u
-12 = -20 + 4u + -4u

Combine like terms: 4u + -4u = 0
-12 = -20 + 0
-12 = -20

Solving
-12 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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