u/x+5u/x-u/5x

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Solution for u/x+5u/x-u/5x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

u/x+(5*u)/x-((u/5)*x) = 0

6*u*x^-1-1/5*u*x = 0

t_1 = x^-1

6*t_1^1*u-1/5*t_1^-1*u = 0

6*t_1*u-1/5*t_1^-1*u = 0

t_1^-1*u*(6*t_1^2-1/5) = 0

6*t_1^2 = 1/5 // : 6

t_1^2 = 1/30

t_1^2 = 1/30 // ^ 1/2

abs(t_1) = (1/30)^(1/2)

t_1 = (1/30)^(1/2) or t_1 = -(1/30)^(1/2)

u/t_1 = 0

t_1^-1*u = 0 // : u

t_1^-1 = 0

t_1 naleu017Cy do O

t_1 = (1/30)^(1/2)

x^-1-(1/30)^(1/2) = 0

1*x^-1 = (1/30)^(1/2) // : 1

x^-1 = (1/30)^(1/2)

-1 < 0

1/(x^1) = (1/30)^(1/2) // * x^1

1 = (1/30)^(1/2)*x^1 // : (1/30)^(1/2)

1/((1/30)^(1/2)) = x^1

x = 1/((1/30)^(1/2))

t_1 = -(1/30)^(1/2)

x^-1+(1/30)^(1/2) = 0

1*x^-1 = -(1/30)^(1/2) // : 1

x^-1 = -(1/30)^(1/2)

-1 < 0

1/(x^1) = -(1/30)^(1/2) // * x^1

1 = -(1/30)^(1/2)*x^1 // : -(1/30)^(1/2)

1/(-(1/30)^(1/2)) = x^1

x = 1/(-(1/30)^(1/2))

x in { 1/((1/30)^(1/2)), 1/(-(1/30)^(1/2)) }

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