u2+35u+94=0

Solution for u2+35u+94=0 equation:

u2+35u+94=0

We add all the numbers together, and all the variables

u^2+35u+94=0

a = 1; b = 35; c = +94;
Δ = b2-4ac
Δ = 352-4·1·94
Δ = 849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{849}}{2*1}=\frac{-35-\sqrt{849}}{2}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{849}}{2*1}=\frac{-35+\sqrt{849}}{2}
$