u2+52u+576=0

Solution for u2+52u+576=0 equation:

u2+52u+576=0

We add all the numbers together, and all the variables

u^2+52u+576=0

a = 1; b = 52; c = +576;
Δ = b2-4ac
Δ = 522-4·1·576
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-20}{2*1}=\frac{-72}{2}
=-36
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+20}{2*1}=\frac{-32}{2}
=-16
$