u2-23u-24=0

Solution for u2-23u-24=0 equation:

u2-23u-24=0

We add all the numbers together, and all the variables

u^2-23u-24=0

a = 1; b = -23; c = -24;
Δ = b2-4ac
Δ = -232-4·1·(-24)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-25}{2*1}=\frac{-2}{2}
=-1
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+25}{2*1}=\frac{48}{2}
=24
$