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u2-52u+576=0
We add all the numbers together, and all the variables
u^2-52u+576=0
a = 1; b = -52; c = +576;
Δ = b2-4ac
Δ = -522-4·1·576
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-20}{2*1}=\frac{32}{2} =16 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+20}{2*1}=\frac{72}{2} =36 $
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