v(v+1)=132

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Solution for v(v+1)=132 equation:


Simplifying
v(v + 1) = 132

Reorder the terms:
v(1 + v) = 132
(1 * v + v * v) = 132
(1v + v2) = 132

Solving
1v + v2 = 132

Solving for variable 'v'.

Reorder the terms:
-132 + 1v + v2 = 132 + -132

Combine like terms: 132 + -132 = 0
-132 + 1v + v2 = 0

Factor a trinomial.
(-12 + -1v)(11 + -1v) = 0

Subproblem 1

Set the factor '(-12 + -1v)' equal to zero and attempt to solve: Simplifying -12 + -1v = 0 Solving -12 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1v = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1v = 0 + 12 -1v = 0 + 12 Combine like terms: 0 + 12 = 12 -1v = 12 Divide each side by '-1'. v = -12 Simplifying v = -12

Subproblem 2

Set the factor '(11 + -1v)' equal to zero and attempt to solve: Simplifying 11 + -1v = 0 Solving 11 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + -1v = 0 + -11 Combine like terms: 11 + -11 = 0 0 + -1v = 0 + -11 -1v = 0 + -11 Combine like terms: 0 + -11 = -11 -1v = -11 Divide each side by '-1'. v = 11 Simplifying v = 11

Solution

v = {-12, 11}

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