v+1=2(4+v)

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Solution for v+1=2(4+v) equation: 



v+1=2(4+v)

We move all terms to the left:

v+1-(2(4+v))=0

We add all the numbers together, and all the variables

v-(2(v+4))+1=0



We calculate terms in parentheses: -(2(v+4)), so:

2(v+4)

We multiply parentheses

2v+8

Back to the equation:

-(2v+8)



We get rid of parentheses

v-2v-8+1=0

We add all the numbers together, and all the variables

-1v-7=0

We move all terms containing v to the left, all other terms to the right

-v=7

v=7/-1

v=-7

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