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v+2(2v+1)=2(5v-4)
We move all terms to the left:
v+2(2v+1)-(2(5v-4))=0
We multiply parentheses
v+4v-(2(5v-4))+2=0
We calculate terms in parentheses: -(2(5v-4)), so:We add all the numbers together, and all the variables
2(5v-4)
We multiply parentheses
10v-8
Back to the equation:
-(10v-8)
5v-(10v-8)+2=0
We get rid of parentheses
5v-10v+8+2=0
We add all the numbers together, and all the variables
-5v+10=0
We move all terms containing v to the left, all other terms to the right
-5v=-10
v=-10/-5
v=+2
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