v+32=-6(1+3v)

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Solution for v+32=-6(1+3v) equation: 



v+32=-6(1+3v)

We move all terms to the left:

v+32-(-6(1+3v))=0

We add all the numbers together, and all the variables

v-(-6(3v+1))+32=0



We calculate terms in parentheses: -(-6(3v+1)), so:

-6(3v+1)

We multiply parentheses

-18v-6

Back to the equation:

-(-18v-6)



We get rid of parentheses

v+18v+6+32=0

We add all the numbers together, and all the variables

19v+38=0

We move all terms containing v to the left, all other terms to the right

19v=-38

v=-38/19

v=-2

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