v-12=-6(1-v)-4v

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Solution for v-12=-6(1-v)-4v equation:



v-12=-6(1-v)-4v
We move all terms to the left:
v-12-(-6(1-v)-4v)=0
We add all the numbers together, and all the variables
v-(-6(-1v+1)-4v)-12=0
We calculate terms in parentheses: -(-6(-1v+1)-4v), so:
-6(-1v+1)-4v
We add all the numbers together, and all the variables
-4v-6(-1v+1)
We multiply parentheses
-4v+6v-6
We add all the numbers together, and all the variables
2v-6
Back to the equation:
-(2v-6)
We get rid of parentheses
v-2v+6-12=0
We add all the numbers together, and all the variables
-1v-6=0
We move all terms containing v to the left, all other terms to the right
-v=6
v=6/-1
v=-6

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