v/4v+8=26-2v.

Solution for v/4v+8=26-2v. equation:

v/4v+8=26-2v.

We move all terms to the left:

v/4v+8-(26-2v.)=0


Domain of the equation: 4v!=0

v!=0/4

v!=0

v∈R


We add all the numbers together, and all the variables

v/4v-(-2v.+26)+8=0

We get rid of parentheses

v/4v+2v.-26+8=0

We multiply all the terms by the denominator


v+(2v.)*4v-26*4v+8*4v=0

We add all the numbers together, and all the variables

v+(+2v.)*4v-26*4v+8*4v=0

We multiply parentheses

8v^2+v-26*4v+8*4v=0

Wy multiply elements

8v^2+v-104v+32v=0

We add all the numbers together, and all the variables

8v^2-71v=0

a = 8; b = -71; c = 0;
Δ = b2-4ac
Δ = -712-4·8·0
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-71}{2*8}=\frac{0}{16}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+71}{2*8}=\frac{142}{16}
=8+7/8
$