v2+30v=-13

Solution for v2+30v=-13 equation:

v2+30v=-13

We move all terms to the left:

v2+30v-(-13)=0

We add all the numbers together, and all the variables

v^2+30v+13=0

a = 1; b = 30; c = +13;
Δ = b2-4ac
Δ = 302-4·1·13
Δ = 848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{848}=\sqrt{16*53}=\sqrt{16}*\sqrt{53}=4\sqrt{53}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-4\sqrt{53}}{2*1}=\frac{-30-4\sqrt{53}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+4\sqrt{53}}{2*1}=\frac{-30+4\sqrt{53}}{2}
$