v2+4v-44=0

Solution for v2+4v-44=0 equation:

v2+4v-44=0

We add all the numbers together, and all the variables

v^2+4v-44=0

a = 1; b = 4; c = -44;
Δ = b2-4ac
Δ = 42-4·1·(-44)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{3}}{2*1}=\frac{-4-8\sqrt{3}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{3}}{2*1}=\frac{-4+8\sqrt{3}}{2}
$