v2+6v-59=0

Solution for v2+6v-59=0 equation:

v2+6v-59=0

We add all the numbers together, and all the variables

v^2+6v-59=0

a = 1; b = 6; c = -59;
Δ = b2-4ac
Δ = 62-4·1·(-59)
Δ = 272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{272}=\sqrt{16*17}=\sqrt{16}*\sqrt{17}=4\sqrt{17}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{17}}{2*1}=\frac{-6-4\sqrt{17}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{17}}{2*1}=\frac{-6+4\sqrt{17}}{2}
$