v2+9=-6v

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Solution for v2+9=-6v equation:



v2+9=-6v
We move all terms to the left:
v2+9-(-6v)=0
We add all the numbers together, and all the variables
v^2-(-6v)+9=0
We get rid of parentheses
v^2+6v+9=0
a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-6}{2}=-3$

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