v2-16v=-35

Solution for v2-16v=-35 equation:

v2-16v=-35

We move all terms to the left:

v2-16v-(-35)=0

We add all the numbers together, and all the variables

v^2-16v+35=0

a = 1; b = -16; c = +35;
Δ = b2-4ac
Δ = -162-4·1·35
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{29}}{2*1}=\frac{16-2\sqrt{29}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{29}}{2*1}=\frac{16+2\sqrt{29}}{2}
$