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v2=67
We move all terms to the left:
v2-(67)=0
We add all the numbers together, and all the variables
v^2-67=0
a = 1; b = 0; c = -67;
Δ = b2-4ac
Δ = 02-4·1·(-67)
Δ = 268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{268}=\sqrt{4*67}=\sqrt{4}*\sqrt{67}=2\sqrt{67}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{67}}{2*1}=\frac{0-2\sqrt{67}}{2} =-\frac{2\sqrt{67}}{2} =-\sqrt{67} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{67}}{2*1}=\frac{0+2\sqrt{67}}{2} =\frac{2\sqrt{67}}{2} =\sqrt{67} $
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