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v=1/2723v-6=12
We move all terms to the left:
v-(1/2723v-6)=0
Domain of the equation: 2723v-6)!=0We get rid of parentheses
v∈R
v-1/2723v+6=0
We multiply all the terms by the denominator
v*2723v+6*2723v-1=0
Wy multiply elements
2723v^2+16338v-1=0
a = 2723; b = 16338; c = -1;
Δ = b2-4ac
Δ = 163382-4·2723·(-1)
Δ = 266941136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{266941136}=\sqrt{16*16683821}=\sqrt{16}*\sqrt{16683821}=4\sqrt{16683821}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16338)-4\sqrt{16683821}}{2*2723}=\frac{-16338-4\sqrt{16683821}}{5446} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16338)+4\sqrt{16683821}}{2*2723}=\frac{-16338+4\sqrt{16683821}}{5446} $
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