v=3;-12(4v+2)

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Solution for v=3;-12(4v+2) equation: 



v=3-12(4v+2)

We move all terms to the left:

v-(3-12(4v+2))=0



We calculate terms in parentheses: -(3-12(4v+2)), so:

3-12(4v+2)

determiningTheFunctionDomain
-12(4v+2)+3

We multiply parentheses

-48v-24+3

We add all the numbers together, and all the variables

-48v-21

Back to the equation:

-(-48v-21)



We get rid of parentheses

v+48v+21=0

We add all the numbers together, and all the variables

49v+21=0

We move all terms containing v to the left, all other terms to the right

49v=-21

v=-21/49

v=-3/7

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