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w(2w-2)=112
We move all terms to the left:
w(2w-2)-(112)=0
We multiply parentheses
2w^2-2w-112=0
a = 2; b = -2; c = -112;
Δ = b2-4ac
Δ = -22-4·2·(-112)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-30}{2*2}=\frac{-28}{4} =-7 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+30}{2*2}=\frac{32}{4} =8 $
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