w(2w-8)=280

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Solution for w(2w-8)=280 equation:



w(2w-8)=280
We move all terms to the left:
w(2w-8)-(280)=0
We multiply parentheses
2w^2-8w-280=0
a = 2; b = -8; c = -280;
Δ = b2-4ac
Δ = -82-4·2·(-280)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-48}{2*2}=\frac{-40}{4} =-10 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+48}{2*2}=\frac{56}{4} =14 $

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