w(3/5)=160

Solution for w(3/5)=160 equation:

w(3/5)=160

We move all terms to the left:

w(3/5)-(160)=0

We add all the numbers together, and all the variables

w(+3/5)-160=0

We multiply parentheses

3w^2-160=0

a = 3; b = 0; c = -160;
Δ = b2-4ac
Δ = 02-4·3·(-160)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*3}=\frac{0-8\sqrt{30}}{6}
=-\frac{8\sqrt{30}}{6}
=-\frac{4\sqrt{30}}{3}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*3}=\frac{0+8\sqrt{30}}{6}
=\frac{8\sqrt{30}}{6}
=\frac{4\sqrt{30}}{3}
$