w(35w-49)=0

Solution for w(35w-49)=0 equation:

w(35w-49)=0

We multiply parentheses

35w^2-49w=0

a = 35; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·35·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*35}=\frac{0}{70}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*35}=\frac{98}{70}
=1+2/5
$