w(3w-4)=55

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Solution for w(3w-4)=55 equation:



w(3w-4)=55
We move all terms to the left:
w(3w-4)-(55)=0
We multiply parentheses
3w^2-4w-55=0
a = 3; b = -4; c = -55;
Δ = b2-4ac
Δ = -42-4·3·(-55)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-26}{2*3}=\frac{-22}{6} =-3+2/3 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+26}{2*3}=\frac{30}{6} =5 $

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