w(w+16)=260

Solution for w(w+16)=260 equation:

w(w+16)=260

We move all terms to the left:

w(w+16)-(260)=0

We multiply parentheses

w^2+16w-260=0

a = 1; b = 16; c = -260;
Δ = b2-4ac
Δ = 162-4·1·(-260)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-36}{2*1}=\frac{-52}{2}
=-26
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+36}{2*1}=\frac{20}{2}
=10
$