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w(w+18)=144
We move all terms to the left:
w(w+18)-(144)=0
We multiply parentheses
w^2+18w-144=0
a = 1; b = 18; c = -144;
Δ = b2-4ac
Δ = 182-4·1·(-144)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*1}=\frac{-48}{2} =-24 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*1}=\frac{12}{2} =6 $
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