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w(w+8)=256
We move all terms to the left:
w(w+8)-(256)=0
We multiply parentheses
w^2+8w-256=0
a = 1; b = 8; c = -256;
Δ = b2-4ac
Δ = 82-4·1·(-256)
Δ = 1088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1088}=\sqrt{64*17}=\sqrt{64}*\sqrt{17}=8\sqrt{17}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{17}}{2*1}=\frac{-8-8\sqrt{17}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{17}}{2*1}=\frac{-8+8\sqrt{17}}{2} $
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