w(w-4)=w+4(w-4-2)

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Solution for w(w-4)=w+4(w-4-2) equation: 



w(w-4)=w+4(w-4-2)

We move all terms to the left:

w(w-4)-(w+4(w-4-2))=0

We add all the numbers together, and all the variables

w(w-4)-(w+4(w-6))=0

We multiply parentheses

w^2-4w-(w+4(w-6))=0



We calculate terms in parentheses: -(w+4(w-6)), so:

w+4(w-6)

We multiply parentheses

w+4w-24

We add all the numbers together, and all the variables

5w-24

Back to the equation:

-(5w-24)



We get rid of parentheses

w^2-4w-5w+24=0

We add all the numbers together, and all the variables

w^2-9w+24=0

a = 1; b = -9; c = +24;
Δ = b2-4ac
Δ = -92-4·1·24
Δ = -15
Delta is less than zero, so there is no solution for the equation

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