w*3w+5=300

Solution for w*3w+5=300 equation:

w*3w+5=300

We move all terms to the left:

w*3w+5-(300)=0

We add all the numbers together, and all the variables

w*3w-295=0

Wy multiply elements

3w^2-295=0

a = 3; b = 0; c = -295;
Δ = b2-4ac
Δ = 02-4·3·(-295)
Δ = 3540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3540}=\sqrt{4*885}=\sqrt{4}*\sqrt{885}=2\sqrt{885}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{885}}{2*3}=\frac{0-2\sqrt{885}}{6}
=-\frac{2\sqrt{885}}{6}
=-\frac{\sqrt{885}}{3}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{885}}{2*3}=\frac{0+2\sqrt{885}}{6}
=\frac{2\sqrt{885}}{6}
=\frac{\sqrt{885}}{3}
$