w+2w+3+3=3(w+2)

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Solution for w+2w+3+3=3(w+2) equation: 



w+2w+3+3=3(w+2)

We move all terms to the left:

w+2w+3+3-(3(w+2))=0

We add all the numbers together, and all the variables

3w-(3(w+2))+6=0



We calculate terms in parentheses: -(3(w+2)), so:

3(w+2)

We multiply parentheses

3w+6

Back to the equation:

-(3w+6)



We get rid of parentheses

3w-3w-6+6=0

We add all the numbers together, and all the variables

=0

w=0/1

w=0

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